Diode Voltage¶
The diode voltage $V_D$ is reduced from the applied bias $V_{bias}$ due to series resistance $R_s$. We have $V_D = V_{bias} - J_D R_s$.
Dark Current Density¶
\begin{equation}
J_{dark} = \sum_{n} {J_{n}\left[\exp{\left(\frac{qV_D}{nkT}\right)} - 1\right]} + \frac{V_D}{R_{SH}}
\end{equation}